Search a number
-
+
151125433 = 2312015471
BaseRepresentation
bin10010000000111…
…11110110111001
3101112100222010021
421000133312321
5302142003213
622555050441
73513354634
oct1100376671
9345328107
10151125433
1178340858
1242740a21
1325404244
14160dcc1b
15d402d8d
hex901fdb9

151125433 has 8 divisors (see below), whose sum is σ = 157856256. Its totient is φ = 144408000.

The previous prime is 151125413. The next prime is 151125439. The reversal of 151125433 is 334521151.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 151125433 - 29 = 151124921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 151125398 and 151125407.

It is not an unprimeable number, because it can be changed into a prime (151125439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24888 + ... + 30358.

It is an arithmetic number, because the mean of its divisors is an integer number (19732032).

Almost surely, 2151125433 is an apocalyptic number.

It is an amenable number.

151125433 is a deficient number, since it is larger than the sum of its proper divisors (6730823).

151125433 is a wasteful number, since it uses less digits than its factorization.

151125433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6695.

The product of its digits is 1800, while the sum is 25.

The square root of 151125433 is about 12293.3084643639. The cubic root of 151125433 is about 532.6548094786.

Adding to 151125433 its reverse (334521151), we get a palindrome (485646584).

The spelling of 151125433 in words is "one hundred fifty-one million, one hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 23 1201 5471 27623 125833 6570671 151125433