Base | Representation |
---|---|
bin | 1101101111101100101100… |
… | …1110000010100001110000 |
3 | 1222111210120020020100022122 |
4 | 3123323023032002201300 |
5 | 3440103114211340134 |
6 | 52050510405253412 |
7 | 3116612546562251 |
oct | 333731316024160 |
9 | 58453506210278 |
10 | 15113104402544 |
11 | 48a748248a225 |
12 | 1841030104268 |
13 | 85820c926565 |
14 | 3a369a0bab28 |
15 | 1b31d707502e |
hex | dbecb382870 |
15113104402544 has 20 divisors (see below), whose sum is σ = 29286179065320. Its totient is φ = 7555380772800.
The previous prime is 15113104402499. The next prime is 15113104402589. The reversal of 15113104402544 is 44520440131151.
15113104402544 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (15113104402499) and next prime (15113104402589).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73107839 + ... + 73314270.
It is an arithmetic number, because the mean of its divisors is an integer number (1464308953266).
Almost surely, 215113104402544 is an apocalyptic number.
It is an amenable number.
15113104402544 is a deficient number, since it is larger than the sum of its proper divisors (14173074662776).
15113104402544 is a wasteful number, since it uses less digits than its factorization.
15113104402544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 146428568 (or 146428562 counting only the distinct ones).
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 15113104402544 its reverse (44520440131151), we get a palindrome (59633544533695).
The spelling of 15113104402544 in words is "fifteen trillion, one hundred thirteen billion, one hundred four million, four hundred two thousand, five hundred forty-four".
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