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15113403555421 is a prime number
BaseRepresentation
bin1101101111101101110100…
…0011001101111001011101
31222111211100002010212220211
43123323131003031321131
53440104222302233141
652051000213212421
73116623141413133
oct333733503157135
958454302125824
1015113403555421
1148a7616335206
1218410b4331111
138582598b88b2
143a36c7b0d753
151b3203467d81
hexdbedd0cde5d

15113403555421 has 2 divisors, whose sum is σ = 15113403555422. Its totient is φ = 15113403555420.

The previous prime is 15113403555379. The next prime is 15113403555461. The reversal of 15113403555421 is 12455530431151.

It is an a-pointer prime, because the next prime (15113403555461) can be obtained adding 15113403555421 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9507731738521 + 5605671816900 = 3083461^2 + 2367630^2 .

It is a cyclic number.

It is not a de Polignac number, because 15113403555421 - 223 = 15113395166813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15113403555461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7556701777710 + 7556701777711.

It is an arithmetic number, because the mean of its divisors is an integer number (7556701777711).

Almost surely, 215113403555421 is an apocalyptic number.

It is an amenable number.

15113403555421 is a deficient number, since it is larger than the sum of its proper divisors (1).

15113403555421 is an equidigital number, since it uses as much as digits as its factorization.

15113403555421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 40.

Adding to 15113403555421 its reverse (12455530431151), we get a palindrome (27568933986572).

The spelling of 15113403555421 in words is "fifteen trillion, one hundred thirteen billion, four hundred three million, five hundred fifty-five thousand, four hundred twenty-one".