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151150656551 = 196033771047
BaseRepresentation
bin1000110011000101000…
…1111111110000100111
3112110010221121220220212
42030301101333300213
54434024032002201
6153234311050035
713630440245036
oct2146121776047
9473127556825
10151150656551
1159114672484
122536407091b
131133aa8831b
14745c51871d
153de9b1eabb
hex233147fc27

151150656551 has 4 divisors (see below), whose sum is σ = 151151623632. Its totient is φ = 151149689472.

The previous prime is 151150656529. The next prime is 151150656557. The reversal of 151150656551 is 155656051151.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 155656051151 = 179156238303.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-151150656551 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 151150656499 and 151150656508.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (151150656557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189491 + ... + 581556.

It is an arithmetic number, because the mean of its divisors is an integer number (37787905908).

Almost surely, 2151150656551 is an apocalyptic number.

151150656551 is a deficient number, since it is larger than the sum of its proper divisors (967081).

151150656551 is an equidigital number, since it uses as much as digits as its factorization.

151150656551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 967080.

The product of its (nonzero) digits is 112500, while the sum is 41.

The spelling of 151150656551 in words is "one hundred fifty-one billion, one hundred fifty million, six hundred fifty-six thousand, five hundred fifty-one".

Divisors: 1 196033 771047 151150656551