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15121113135403 = 1117117163690163
BaseRepresentation
bin1101110000001010100010…
…0100111011100100101011
31222112120020101002010110011
43130002220210323210223
53440221014430313103
652054313220232351
73120315164643532
oct334025044734453
958476211063404
1015121113135403
1148aa912181810
1218426a623b6b7
13858bb7c06542
143a3c199b9319
151b35051e7d6d
hexdc0a893b92b

15121113135403 has 16 divisors (see below), whose sum is σ = 17466272977536. Its totient is φ = 12937721639040.

The previous prime is 15121113135361. The next prime is 15121113135407. The reversal of 15121113135403 is 30453131112151.

It is a happy number.

It is not a de Polignac number, because 15121113135403 - 221 = 15121111038251 is a prime.

It is a super-3 number, since 3×151211131354033 (a number of 41 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (15121113135407) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21564400 + ... + 22254562.

It is an arithmetic number, because the mean of its divisors is an integer number (1091642061096).

Almost surely, 215121113135403 is an apocalyptic number.

15121113135403 is a deficient number, since it is larger than the sum of its proper divisors (2345159842133).

15121113135403 is a wasteful number, since it uses less digits than its factorization.

15121113135403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 807354.

The product of its (nonzero) digits is 5400, while the sum is 31.

Adding to 15121113135403 its reverse (30453131112151), we get a palindrome (45574244247554).

The spelling of 15121113135403 in words is "fifteen trillion, one hundred twenty-one billion, one hundred thirteen million, one hundred thirty-five thousand, four hundred three".

Divisors: 1 11 17 187 117163 690163 1288793 1991771 7591793 11732771 21909481 129060481 80861567569 889477243259 1374646648673 15121113135403