Base | Representation |
---|---|
bin | 1000110011010100010… |
… | …1101100010011110111 |
3 | 112110022101211112120101 |
4 | 2030311011230103313 |
5 | 4434141410240043 |
6 | 153244512214531 |
7 | 13632144245161 |
oct | 2146505542367 |
9 | 473271745511 |
10 | 151214540023 |
11 | 59147736038 |
12 | 2538153a447 |
13 | 1134b094ab1 |
14 | 7466bc7931 |
15 | 3e0053d24d |
hex | 233516c4f7 |
151214540023 has 2 divisors, whose sum is σ = 151214540024. Its totient is φ = 151214540022.
The previous prime is 151214540021. The next prime is 151214540041. The reversal of 151214540023 is 320045412151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 151214540023 - 21 = 151214540021 is a prime.
It is a super-2 number, since 2×1512145400232 (a number of 23 digits) contains 22 as substring.
Together with 151214540021, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 151214539973 and 151214540000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151214540021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75607270011 + 75607270012.
It is an arithmetic number, because the mean of its divisors is an integer number (75607270012).
Almost surely, 2151214540023 is an apocalyptic number.
151214540023 is a deficient number, since it is larger than the sum of its proper divisors (1).
151214540023 is an equidigital number, since it uses as much as digits as its factorization.
151214540023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 151214540023 its reverse (320045412151), we get a palindrome (471259952174).
The spelling of 151214540023 in words is "one hundred fifty-one billion, two hundred fourteen million, five hundred forty thousand, twenty-three".
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