15122412113 has 4 divisors (see below), whose sum is σ = 15918328560. Its totient is φ = 14326495668.

The previous prime is 15122412091. The next prime is 15122412121. The reversal of 15122412113 is 31121422151.

15122412113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121422151 = 1549 ⋅20091299.

It is a cyclic number.

It is not a de Polignac number, because 15122412113 - 2¹⁰ = 15122411089 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (15122412133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 397958195 + ... + 397958232.

It is an arithmetic number, because the mean of its divisors is an integer number (3979582140).

Almost surely, 2^15122412113 is an apocalyptic number.

It is an amenable number.

15122412113 is a deficient number, since it is larger than the sum of its proper divisors (795916447).

15122412113 is an equidigital number, since it uses as much as digits as its factorization.

15122412113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 795916446.

The product of its digits is 480, while the sum is 23.

Adding to 15122412113 its reverse (31121422151), we get a palindrome (46243834264).

The spelling of 15122412113 in words is "fifteen billion, one hundred twenty-two million, four hundred twelve thousand, one hundred thirteen".