Base | Representation |
---|---|
bin | 1000110011011110000… |
… | …0001101000011101111 |
3 | 112110102020001101001002 |
4 | 2030313200031003233 |
5 | 4434232242404320 |
6 | 153252520310515 |
7 | 13633145443433 |
oct | 2146740150357 |
9 | 473366041032 |
10 | 151255044335 |
11 | 5916859057a |
12 | 2539301243b |
13 | 113565a7045 |
14 | 746c32c9c3 |
15 | 3e03d8e675 |
hex | 233780d0ef |
151255044335 has 4 divisors (see below), whose sum is σ = 181506053208. Its totient is φ = 121004035464.
The previous prime is 151255044323. The next prime is 151255044361. The reversal of 151255044335 is 533440552151.
151255044335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 151255044335 - 212 = 151255040239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15125504429 + ... + 15125504438.
It is an arithmetic number, because the mean of its divisors is an integer number (45376513302).
Almost surely, 2151255044335 is an apocalyptic number.
151255044335 is a deficient number, since it is larger than the sum of its proper divisors (30251008873).
151255044335 is an equidigital number, since it uses as much as digits as its factorization.
151255044335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30251008872.
The product of its (nonzero) digits is 180000, while the sum is 38.
Adding to 151255044335 its reverse (533440552151), we get a palindrome (684695596486).
The spelling of 151255044335 in words is "one hundred fifty-one billion, two hundred fifty-five million, forty-four thousand, three hundred thirty-five".
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