15130117 has 4 divisors (see below), whose sum is σ = 15138976. Its totient is φ = 15121260.

The previous prime is 15130097. The next prime is 15130133. The reversal of 15130117 is 71103151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15130117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15130094 and 15130103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15134117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 963 + ... + 5584.

It is an arithmetic number, because the mean of its divisors is an integer number (3784744).

Almost surely, 2^15130117 is an apocalyptic number.

It is an amenable number.

15130117 is a deficient number, since it is larger than the sum of its proper divisors (8859).

15130117 is an equidigital number, since it uses as much as digits as its factorization.

15130117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8858.

The product of its (nonzero) digits is 105, while the sum is 19.

The square root of 15130117 is about 3889.7451073303. The cubic root of 15130117 is about 247.3322578658.

Adding to 15130117 its reverse (71103151), we get a palindrome (86233268).

The spelling of 15130117 in words is "fifteen million, one hundred thirty thousand, one hundred seventeen".