Base | Representation |
---|---|
bin | 10110000001010010001… |
… | …110011101010101101011 |
3 | 12100122212001211120101111 |
4 | 112001102032131111223 |
5 | 144243022222310331 |
6 | 3115054055131151 |
7 | 214216463601421 |
oct | 26012216352553 |
9 | 5318761746344 |
10 | 1513208010091 |
11 | 533825521908 |
12 | 20532a373ab7 |
13 | ac9059184ab |
14 | 5334d8a1111 |
15 | 29566bd8db1 |
hex | 1605239d56b |
1513208010091 has 2 divisors, whose sum is σ = 1513208010092. Its totient is φ = 1513208010090.
The previous prime is 1513208010089. The next prime is 1513208010109. The reversal of 1513208010091 is 1900108023151.
Together with next prime (1513208010109) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1513208010091 - 21 = 1513208010089 is a prime.
Together with 1513208010089, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1513208010001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 756604005045 + 756604005046.
It is an arithmetic number, because the mean of its divisors is an integer number (756604005046).
Almost surely, 21513208010091 is an apocalyptic number.
1513208010091 is a deficient number, since it is larger than the sum of its proper divisors (1).
1513208010091 is an equidigital number, since it uses as much as digits as its factorization.
1513208010091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 31.
The spelling of 1513208010091 in words is "one trillion, five hundred thirteen billion, two hundred eight million, ten thousand, ninety-one".
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