Base | Representation |
---|---|
bin | 1101110000110111101001… |
… | …0100110001101000100101 |
3 | 1222120201111021010202000012 |
4 | 3130031322110301220211 |
5 | 3440420314321102331 |
6 | 52104034540300005 |
7 | 3121224231012533 |
oct | 334157224615045 |
9 | 58521437122005 |
10 | 15133222050341 |
11 | 4904a6636382a |
12 | 1844b05541605 |
13 | 85a0977b3575 |
14 | 3a4647c69153 |
15 | 1b39b32ce82b |
hex | dc37a531a25 |
15133222050341 has 4 divisors (see below), whose sum is σ = 16023411582732. Its totient is φ = 14243032517952.
The previous prime is 15133222050301. The next prime is 15133222050391. The reversal of 15133222050341 is 14305022233151.
15133222050341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13873047419716 + 1260174630625 = 3724654^2 + 1122575^2 .
It is a cyclic number.
It is not a de Polignac number, because 15133222050341 - 238 = 14858344143397 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15133222050298 and 15133222050307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15133222050301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 445094766170 + ... + 445094766203.
It is an arithmetic number, because the mean of its divisors is an integer number (4005852895683).
Almost surely, 215133222050341 is an apocalyptic number.
It is an amenable number.
15133222050341 is a deficient number, since it is larger than the sum of its proper divisors (890189532391).
15133222050341 is an equidigital number, since it uses as much as digits as its factorization.
15133222050341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 890189532390.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 15133222050341 its reverse (14305022233151), we get a palindrome (29438244283492).
The spelling of 15133222050341 in words is "fifteen trillion, one hundred thirty-three billion, two hundred twenty-two million, fifty thousand, three hundred forty-one".
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