151341335345 has 4 divisors (see below), whose sum is σ = 181609602420. Its totient is φ = 121073068272.

The previous prime is 151341335273. The next prime is 151341335371. The reversal of 151341335345 is 543533143151.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 543533143151 = 79 ⋅6880166369.

It can be written as a sum of positive squares in 2 ways, for example, as 65429035681 + 85912299664 = 255791^2 + 293108^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-151341335345 is a prime.

It is a super-3 number, since 3×151341335345³ (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 151341335299 and 151341335308.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15134133530 + ... + 15134133539.

It is an arithmetic number, because the mean of its divisors is an integer number (45402400605).

Almost surely, 2^151341335345 is an apocalyptic number.

It is an amenable number.

151341335345 is a deficient number, since it is larger than the sum of its proper divisors (30268267075).

151341335345 is an equidigital number, since it uses as much as digits as its factorization.

151341335345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30268267074.

The product of its digits is 162000, while the sum is 38.

Adding to 151341335345 its reverse (543533143151), we get a palindrome (694874478496).

The spelling of 151341335345 in words is "one hundred fifty-one billion, three hundred forty-one million, three hundred thirty-five thousand, three hundred forty-five".