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15140114117 is a prime number
BaseRepresentation
bin11100001100110101…
…11100111011000101
31110002010210111010022
432012122330323011
5222001332122432
610542201104525
71044120563252
oct160632747305
943063714108
1015140114117
11646a221907
122b26488145
13157389630b
14a38a98429
155d928eb12
hex3866bcec5

15140114117 has 2 divisors, whose sum is σ = 15140114118. Its totient is φ = 15140114116.

The previous prime is 15140114107. The next prime is 15140114141. The reversal of 15140114117 is 71141104151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13560369601 + 1579744516 = 116449^2 + 39746^2 .

It is a cyclic number.

It is not a de Polignac number, because 15140114117 - 212 = 15140110021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15140114107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7570057058 + 7570057059.

It is an arithmetic number, because the mean of its divisors is an integer number (7570057059).

Almost surely, 215140114117 is an apocalyptic number.

It is an amenable number.

15140114117 is a deficient number, since it is larger than the sum of its proper divisors (1).

15140114117 is an equidigital number, since it uses as much as digits as its factorization.

15140114117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 560, while the sum is 26.

Adding to 15140114117 its reverse (71141104151), we get a palindrome (86281218268).

The spelling of 15140114117 in words is "fifteen billion, one hundred forty million, one hundred fourteen thousand, one hundred seventeen".