15143241223 has 4 divisors (see below), whose sum is σ = 16519899528. Its totient is φ = 13766582920.

The previous prime is 15143241221. The next prime is 15143241241. The reversal of 15143241223 is 32214234151.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32214234151 = 11 ⋅2928566741.

It is a cyclic number.

It is not a de Polignac number, because 15143241223 - 2¹ = 15143241221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15143241191 and 15143241200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15143241221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 688329136 + ... + 688329157.

It is an arithmetic number, because the mean of its divisors is an integer number (4129974882).

Almost surely, 2^15143241223 is an apocalyptic number.

15143241223 is a deficient number, since it is larger than the sum of its proper divisors (1376658305).

15143241223 is a wasteful number, since it uses less digits than its factorization.

15143241223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1376658304.

The product of its digits is 5760, while the sum is 28.

Adding to 15143241223 its reverse (32214234151), we get a palindrome (47357475374).

The spelling of 15143241223 in words is "fifteen billion, one hundred forty-three million, two hundred forty-one thousand, two hundred twenty-three".