Base | Representation |
---|---|
bin | 1000110100001011000… |
… | …1111001110100100111 |
3 | 112110220102001011210121 |
4 | 2031002301321310213 |
5 | 4440124210433021 |
6 | 153323355302411 |
7 | 13640633513404 |
oct | 2150261716447 |
9 | 473812034717 |
10 | 151444233511 |
11 | 5925535a16a |
12 | 2542644aa07 |
13 | 113868476bc |
14 | 74894d92ab |
15 | 3e157b0741 |
hex | 2342c79d27 |
151444233511 has 2 divisors, whose sum is σ = 151444233512. Its totient is φ = 151444233510.
The previous prime is 151444233509. The next prime is 151444233547. The reversal of 151444233511 is 115332444151.
151444233511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 151444233511 - 21 = 151444233509 is a prime.
Together with 151444233509, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151444233571) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75722116755 + 75722116756.
It is an arithmetic number, because the mean of its divisors is an integer number (75722116756).
Almost surely, 2151444233511 is an apocalyptic number.
151444233511 is a deficient number, since it is larger than the sum of its proper divisors (1).
151444233511 is an equidigital number, since it uses as much as digits as its factorization.
151444233511 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 28800, while the sum is 34.
Adding to 151444233511 its reverse (115332444151), we get a palindrome (266776677662).
The spelling of 151444233511 in words is "one hundred fifty-one billion, four hundred forty-four million, two hundred thirty-three thousand, five hundred eleven".
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