Base | Representation |
---|---|
bin | 11100001110100011… |
… | …00001100110100111 |
3 | 1110010010201022021211 |
4 | 32013101201212213 |
5 | 222014012421020 |
6 | 10543431452251 |
7 | 1044353305621 |
oct | 160721414647 |
9 | 43103638254 |
10 | 15154420135 |
11 | 6477303168 |
12 | 2b2b227087 |
13 | 1576834b0a |
14 | a3a93dc11 |
15 | 5da66885a |
hex | 3874619a7 |
15154420135 has 16 divisors (see below), whose sum is σ = 18379008000. Its totient is φ = 11995083936.
The previous prime is 15154420117. The next prime is 15154420147. The reversal of 15154420135 is 53102445151.
15154420135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 15154420135 - 219 = 15153895847 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15154420097 and 15154420106.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 135562 + ... + 220648.
It is an arithmetic number, because the mean of its divisors is an integer number (1148688000).
Almost surely, 215154420135 is an apocalyptic number.
15154420135 is a deficient number, since it is larger than the sum of its proper divisors (3224587865).
15154420135 is a wasteful number, since it uses less digits than its factorization.
15154420135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85470.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 15154420135 its reverse (53102445151), we get a palindrome (68256865286).
The spelling of 15154420135 in words is "fifteen billion, one hundred fifty-four million, four hundred twenty thousand, one hundred thirty-five".
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