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151645400117 is a prime number
BaseRepresentation
bin1000110100111011000…
…1010010110000110101
3112111102102120111111122
42031032301102300311
54441032210300432
6153355343113325
713645625430101
oct2151661226065
9474372514448
10151645400117
1159348969662
12254818a2845
13113b941c9b3
1474a8102901
153e2829a612
hex234ec52c35

151645400117 has 2 divisors, whose sum is σ = 151645400118. Its totient is φ = 151645400116.

The previous prime is 151645400089. The next prime is 151645400119. The reversal of 151645400117 is 711004546151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 151061259556 + 584140561 = 388666^2 + 24169^2 .

It is a cyclic number.

It is not a de Polignac number, because 151645400117 - 210 = 151645399093 is a prime.

It is a super-2 number, since 2×1516454001172 (a number of 23 digits) contains 22 as substring.

Together with 151645400119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (151645400119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75822700058 + 75822700059.

It is an arithmetic number, because the mean of its divisors is an integer number (75822700059).

Almost surely, 2151645400117 is an apocalyptic number.

It is an amenable number.

151645400117 is a deficient number, since it is larger than the sum of its proper divisors (1).

151645400117 is an equidigital number, since it uses as much as digits as its factorization.

151645400117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 35.

Adding to 151645400117 its reverse (711004546151), we get a palindrome (862649946268).

The spelling of 151645400117 in words is "one hundred fifty-one billion, six hundred forty-five million, four hundred thousand, one hundred seventeen".