Base | Representation |
---|---|
bin | 1000110100111011000… |
… | …1010010110000110101 |
3 | 112111102102120111111122 |
4 | 2031032301102300311 |
5 | 4441032210300432 |
6 | 153355343113325 |
7 | 13645625430101 |
oct | 2151661226065 |
9 | 474372514448 |
10 | 151645400117 |
11 | 59348969662 |
12 | 254818a2845 |
13 | 113b941c9b3 |
14 | 74a8102901 |
15 | 3e2829a612 |
hex | 234ec52c35 |
151645400117 has 2 divisors, whose sum is σ = 151645400118. Its totient is φ = 151645400116.
The previous prime is 151645400089. The next prime is 151645400119. The reversal of 151645400117 is 711004546151.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 151061259556 + 584140561 = 388666^2 + 24169^2 .
It is a cyclic number.
It is not a de Polignac number, because 151645400117 - 210 = 151645399093 is a prime.
It is a super-2 number, since 2×1516454001172 (a number of 23 digits) contains 22 as substring.
Together with 151645400119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151645400119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75822700058 + 75822700059.
It is an arithmetic number, because the mean of its divisors is an integer number (75822700059).
Almost surely, 2151645400117 is an apocalyptic number.
It is an amenable number.
151645400117 is a deficient number, since it is larger than the sum of its proper divisors (1).
151645400117 is an equidigital number, since it uses as much as digits as its factorization.
151645400117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 35.
Adding to 151645400117 its reverse (711004546151), we get a palindrome (862649946268).
The spelling of 151645400117 in words is "one hundred fifty-one billion, six hundred forty-five million, four hundred thousand, one hundred seventeen".
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