Base | Representation |
---|---|
bin | 10110000100111100000… |
… | …100011100011001100000 |
3 | 12101000222111002222101011 |
4 | 112010330010130121200 |
5 | 144324041100101334 |
6 | 3120543243550304 |
7 | 214415632610410 |
oct | 26047404343140 |
9 | 5330874088334 |
10 | 1517131253344 |
11 | 53545904a603 |
12 | 20604422b394 |
13 | b00ac673ac5 |
14 | 53602954640 |
15 | 296e634b564 |
hex | 1613c11c660 |
1517131253344 has 48 divisors (see below), whose sum is σ = 3418293312000. Its totient is φ = 649294729344.
The previous prime is 1517131253329. The next prime is 1517131253369. The reversal of 1517131253344 is 4433521317151.
It is a super-2 number, since 2×15171312533442 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1517131253297 and 1517131253306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4548894 + ... + 4871005.
It is an arithmetic number, because the mean of its divisors is an integer number (71214444000).
Almost surely, 21517131253344 is an apocalyptic number.
1517131253344 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1517131253344 is an abundant number, since it is smaller than the sum of its proper divisors (1901162058656).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1517131253344 is an equidigital number, since it uses as much as digits as its factorization.
1517131253344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9420635 (or 9420627 counting only the distinct ones).
The product of its digits is 151200, while the sum is 40.
The spelling of 1517131253344 in words is "one trillion, five hundred seventeen billion, one hundred thirty-one million, two hundred fifty-three thousand, three hundred forty-four".
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