Base | Representation |
---|---|
bin | 10010000111110… |
… | …00011101001101 |
3 | 101121001001010002 |
4 | 21003320131031 |
5 | 302403400441 |
6 | 23030054045 |
7 | 3524041325 |
oct | 1103703515 |
9 | 347031102 |
10 | 152012621 |
11 | 78897372 |
12 | 42aaa325 |
13 | 25654cc7 |
14 | 16290285 |
15 | d52ab9b |
hex | 90f874d |
152012621 has 4 divisors (see below), whose sum is σ = 152384700. Its totient is φ = 151640544.
The previous prime is 152012603. The next prime is 152012647. The reversal of 152012621 is 126210251.
152012621 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 104264521 + 47748100 = 10211^2 + 6910^2 .
It is a cyclic number.
It is not a de Polignac number, because 152012621 - 26 = 152012557 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 152012593 and 152012602.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (152012821) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185426 + ... + 186243.
It is an arithmetic number, because the mean of its divisors is an integer number (38096175).
Almost surely, 2152012621 is an apocalyptic number.
It is an amenable number.
152012621 is a deficient number, since it is larger than the sum of its proper divisors (372079).
152012621 is an equidigital number, since it uses as much as digits as its factorization.
152012621 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 372078.
The product of its (nonzero) digits is 240, while the sum is 20.
The square root of 152012621 is about 12329.3398444523. The cubic root of 152012621 is about 533.6951003431.
Adding to 152012621 its reverse (126210251), we get a palindrome (278222872).
It can be divided in two parts, 1520 and 12621, that added together give a palindrome (14141).
The spelling of 152012621 in words is "one hundred fifty-two million, twelve thousand, six hundred twenty-one".
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