Base | Representation |
---|---|
bin | 1000110110011100011… |
… | …1101111111101001111 |
3 | 112112110220022110221011 |
4 | 2031213013233331033 |
5 | 4442401302040142 |
6 | 153504055350051 |
7 | 13662016110442 |
oct | 2154707577517 |
9 | 475426273834 |
10 | 152053940047 |
11 | 59538537769 |
12 | 25576682327 |
13 | 11452c613b9 |
14 | 750648b659 |
15 | 3e4e099417 |
hex | 23671eff4f |
152053940047 has 2 divisors, whose sum is σ = 152053940048. Its totient is φ = 152053940046.
The previous prime is 152053939963. The next prime is 152053940153. The reversal of 152053940047 is 740049350251.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (740049350251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 152053940047 - 227 = 151919722319 is a prime.
It is a super-3 number, since 3×1520539400473 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 152053939991 and 152053940009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152053040047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76026970023 + 76026970024.
It is an arithmetic number, because the mean of its divisors is an integer number (76026970024).
Almost surely, 2152053940047 is an apocalyptic number.
152053940047 is a deficient number, since it is larger than the sum of its proper divisors (1).
152053940047 is an equidigital number, since it uses as much as digits as its factorization.
152053940047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 152053940047 in words is "one hundred fifty-two billion, fifty-three million, nine hundred forty thousand, forty-seven".
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