Base | Representation |
---|---|
bin | 10110001000101010100… |
… | …011101011111101001111 |
3 | 12101102022100000100110201 |
4 | 112020222203223331033 |
5 | 144410234344432233 |
6 | 3122444254514331 |
7 | 214620036146152 |
oct | 26105243537517 |
9 | 5342270010421 |
10 | 1521132420943 |
11 | 537121660a93 |
12 | 2069802059a7 |
13 | b05995b3ab5 |
14 | 538a20cdc99 |
15 | 2987c75277d |
hex | 1622a8ebf4f |
1521132420943 has 2 divisors, whose sum is σ = 1521132420944. Its totient is φ = 1521132420942.
The previous prime is 1521132420911. The next prime is 1521132421007. The reversal of 1521132420943 is 3490242311251.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1521132420943 - 25 = 1521132420911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1521132420043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760566210471 + 760566210472.
It is an arithmetic number, because the mean of its divisors is an integer number (760566210472).
Almost surely, 21521132420943 is an apocalyptic number.
1521132420943 is a deficient number, since it is larger than the sum of its proper divisors (1).
1521132420943 is an equidigital number, since it uses as much as digits as its factorization.
1521132420943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 1521132420943 in words is "one trillion, five hundred twenty-one billion, one hundred thirty-two million, four hundred twenty thousand, nine hundred forty-three".
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