Base | Representation |
---|---|
bin | 1000110110101100100… |
… | …0110111110111011111 |
3 | 112112122121010221000200 |
4 | 2031223020313313133 |
5 | 4443021030442310 |
6 | 153514504154543 |
7 | 13663465041024 |
oct | 2155310676737 |
9 | 475577127020 |
10 | 152121343455 |
11 | 59572594964 |
12 | 25595168a53 |
13 | 11463c01083 |
14 | 75113d554b |
15 | 3e54e609c0 |
hex | 236b237ddf |
152121343455 has 12 divisors (see below), whose sum is σ = 263676995400. Its totient is φ = 81131383152.
The previous prime is 152121343433. The next prime is 152121343469. The reversal of 152121343455 is 554343121251.
152121343455 is a `hidden beast` number, since 1 + 5 + 2 + 1 + 213 + 434 + 5 + 5 = 666.
It is a de Polignac number, because none of the positive numbers 2k-152121343455 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1690237105 + ... + 1690237194.
It is an arithmetic number, because the mean of its divisors is an integer number (21973082950).
Almost surely, 2152121343455 is an apocalyptic number.
152121343455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
152121343455 is a deficient number, since it is larger than the sum of its proper divisors (111555651945).
152121343455 is a wasteful number, since it uses less digits than its factorization.
152121343455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3380474310 (or 3380474307 counting only the distinct ones).
The product of its digits is 72000, while the sum is 36.
The spelling of 152121343455 in words is "one hundred fifty-two billion, one hundred twenty-one million, three hundred forty-three thousand, four hundred fifty-five".
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