15212243274133 has 4 divisors (see below), whose sum is σ = 15426500221728. Its totient is φ = 14997986326540.

The previous prime is 15212243274121. The next prime is 15212243274167. The reversal of 15212243274133 is 33147234221251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15212243274133 - 2⁹ = 15212243273621 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15212243274113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107128473691 + ... + 107128473832.

It is an arithmetic number, because the mean of its divisors is an integer number (3856625055432).

Almost surely, 2^{15212243274133} is an apocalyptic number.

It is an amenable number.

15212243274133 is a deficient number, since it is larger than the sum of its proper divisors (214256947595).

15212243274133 is an equidigital number, since it uses as much as digits as its factorization.

15212243274133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 214256947594.

The product of its digits is 241920, while the sum is 40.

Adding to 15212243274133 its reverse (33147234221251), we get a palindrome (48359477495384).

The spelling of 15212243274133 in words is "fifteen trillion, two hundred twelve billion, two hundred forty-three million, two hundred seventy-four thousand, one hundred thirty-three".