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152160564133 is a prime number
BaseRepresentation
bin1000110110110101111…
…0011111001110100101
3112112202022221112200101
42031231132133032211
54443111101023013
6153522424544101
713664452312024
oct2155536371645
9475668845611
10152160564133
1159592742a46
12255a6322031
131146c083c86
1475166c48bb
153e5860b8dd
hex236d79f3a5

152160564133 has 2 divisors, whose sum is σ = 152160564134. Its totient is φ = 152160564132.

The previous prime is 152160564121. The next prime is 152160564163. The reversal of 152160564133 is 331465061251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102975526404 + 49185037729 = 320898^2 + 221777^2 .

It is a cyclic number.

It is not a de Polignac number, because 152160564133 - 233 = 143570629541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 152160564092 and 152160564101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152160564103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76080282066 + 76080282067.

It is an arithmetic number, because the mean of its divisors is an integer number (76080282067).

Almost surely, 2152160564133 is an apocalyptic number.

It is an amenable number.

152160564133 is a deficient number, since it is larger than the sum of its proper divisors (1).

152160564133 is an equidigital number, since it uses as much as digits as its factorization.

152160564133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 152160564133 in words is "one hundred fifty-two billion, one hundred sixty million, five hundred sixty-four thousand, one hundred thirty-three".