Base | Representation |
---|---|
bin | 1000110111000010011… |
… | …1010111010010010111 |
3 | 112112220000000212110011 |
4 | 2031300213113102113 |
5 | 4443213041110201 |
6 | 153531545341051 |
7 | 13665662021065 |
oct | 2156047272227 |
9 | 475800025404 |
10 | 152213222551 |
11 | 5960a439aa5 |
12 | 255bba97787 |
13 | 11479c603c0 |
14 | 751d6b1035 |
15 | 3e5d05e151 |
hex | 23709d7497 |
152213222551 has 4 divisors (see below), whose sum is σ = 163921931992. Its totient is φ = 140504513112.
The previous prime is 152213222423. The next prime is 152213222593. The reversal of 152213222551 is 155222312251.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155222312251 = 1049 ⋅147971699.
It is a cyclic number.
It is not a de Polignac number, because 152213222551 - 27 = 152213222423 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (152213222251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5854354701 + ... + 5854354726.
It is an arithmetic number, because the mean of its divisors is an integer number (40980482998).
Almost surely, 2152213222551 is an apocalyptic number.
152213222551 is a deficient number, since it is larger than the sum of its proper divisors (11708709441).
152213222551 is a wasteful number, since it uses less digits than its factorization.
152213222551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11708709440.
The product of its digits is 12000, while the sum is 31.
The spelling of 152213222551 in words is "one hundred fifty-two billion, two hundred thirteen million, two hundred twenty-two thousand, five hundred fifty-one".
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