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152305453301 is a prime number
BaseRepresentation
bin1000110111011000011…
…1001100100011110101
3112120010102120200020212
42031312013030203311
54443410144001201
6153545042235205
714001161664311
oct2156607144365
9476112520225
10152305453301
1159657504361
1225626955b05
13114930b3801
14752ba3cb41
153e661cbabb
hex23761cc8f5

152305453301 has 2 divisors, whose sum is σ = 152305453302. Its totient is φ = 152305453300.

The previous prime is 152305453271. The next prime is 152305453303. The reversal of 152305453301 is 103354503251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 147916390801 + 4389062500 = 384599^2 + 66250^2 .

It is a cyclic number.

It is not a de Polignac number, because 152305453301 - 222 = 152301258997 is a prime.

It is a super-2 number, since 2×1523054533012 (a number of 23 digits) contains 22 as substring.

Together with 152305453303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152305453303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76152726650 + 76152726651.

It is an arithmetic number, because the mean of its divisors is an integer number (76152726651).

Almost surely, 2152305453301 is an apocalyptic number.

It is an amenable number.

152305453301 is a deficient number, since it is larger than the sum of its proper divisors (1).

152305453301 is an equidigital number, since it uses as much as digits as its factorization.

152305453301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 32.

Adding to 152305453301 its reverse (103354503251), we get a palindrome (255659956552).

The spelling of 152305453301 in words is "one hundred fifty-two billion, three hundred five million, four hundred fifty-three thousand, three hundred one".