Base | Representation |
---|---|
bin | 11100010111101011… |
… | …01100110100101111 |
3 | 1110022110211120202212 |
4 | 32023311230310233 |
5 | 222143114342033 |
6 | 10555205241035 |
7 | 1046303316134 |
oct | 161365546457 |
9 | 43273746685 |
10 | 15231012143 |
11 | 6506566946 |
12 | 2b50a0317b |
13 | 1589670c29 |
14 | a46b9a58b |
15 | 5e2247748 |
hex | 38bd6cd2f |
15231012143 has 2 divisors, whose sum is σ = 15231012144. Its totient is φ = 15231012142.
The previous prime is 15231012133. The next prime is 15231012151. The reversal of 15231012143 is 34121013251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15231012143 - 210 = 15231011119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15231012133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7615506071 + 7615506072.
It is an arithmetic number, because the mean of its divisors is an integer number (7615506072).
Almost surely, 215231012143 is an apocalyptic number.
15231012143 is a deficient number, since it is larger than the sum of its proper divisors (1).
15231012143 is an equidigital number, since it uses as much as digits as its factorization.
15231012143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 15231012143 its reverse (34121013251), we get a palindrome (49352025394).
The spelling of 15231012143 in words is "fifteen billion, two hundred thirty-one million, twelve thousand, one hundred forty-three".
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