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15234130993 is a prime number
BaseRepresentation
bin11100011000000011…
…00110010000110001
31110022200201001000211
432030001212100301
5222144414142433
610555400144121
71046341656034
oct161401462061
943280631024
1015234130993
1165082a7104
122b51a68041
13158a1c36c3
14a4736d01b
155e26618cd
hex38c066431

15234130993 has 2 divisors, whose sum is σ = 15234130994. Its totient is φ = 15234130992.

The previous prime is 15234130981. The next prime is 15234131039. The reversal of 15234130993 is 39903143251.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8320541089 + 6913589904 = 91217^2 + 83148^2 .

It is a cyclic number.

It is not a de Polignac number, because 15234130993 - 221 = 15232033841 is a prime.

It is a super-2 number, since 2×152341309932 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15234130913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7617065496 + 7617065497.

It is an arithmetic number, because the mean of its divisors is an integer number (7617065497).

Almost surely, 215234130993 is an apocalyptic number.

It is an amenable number.

15234130993 is a deficient number, since it is larger than the sum of its proper divisors (1).

15234130993 is an equidigital number, since it uses as much as digits as its factorization.

15234130993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 87480, while the sum is 40.

The spelling of 15234130993 in words is "fifteen billion, two hundred thirty-four million, one hundred thirty thousand, nine hundred ninety-three".