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15240131 is a prime number
BaseRepresentation
bin111010001000…
…101111000011
31001200021112022
4322020233003
512400141011
61302352055
7243352604
oct72105703
931607468
1015240131
11866a155
12512b62b
133207a3a
142049dab
1515108db
hexe88bc3

15240131 has 2 divisors, whose sum is σ = 15240132. Its totient is φ = 15240130.

The previous prime is 15240107. The next prime is 15240133. The reversal of 15240131 is 13104251.

15240131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (13104251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15240131 - 26 = 15240067 is a prime.

It is a super-2 number, since 2×152401312 = 464523185794322, which contains 22 as substring.

Together with 15240133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (15240133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7620065 + 7620066.

It is an arithmetic number, because the mean of its divisors is an integer number (7620066).

Almost surely, 215240131 is an apocalyptic number.

15240131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15240131 is an equidigital number, since it uses as much as digits as its factorization.

15240131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 15240131 is about 3903.8610374858. The cubic root of 15240131 is about 247.9302776166.

Adding to 15240131 its reverse (13104251), we get a palindrome (28344382).

The spelling of 15240131 in words is "fifteen million, two hundred forty thousand, one hundred thirty-one".