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15250414117 is a prime number
BaseRepresentation
bin11100011001111111…
…01101101000100101
31110100211100022021111
432030333231220211
5222213101222432
611001141145021
71046630244511
oct161477555045
943324308244
1015250414117
116516508934
122b573bb171
1315906a50a3
14a495ab141
155e3ccb347
hex38cfeda25

15250414117 has 2 divisors, whose sum is σ = 15250414118. Its totient is φ = 15250414116.

The previous prime is 15250414037. The next prime is 15250414171. The reversal of 15250414117 is 71141405251.

It is a happy number.

Together with next prime (15250414171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14407440961 + 842973156 = 120031^2 + 29034^2 .

It is a cyclic number.

It is not a de Polignac number, because 15250414117 - 223 = 15242025509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15259414117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7625207058 + 7625207059.

It is an arithmetic number, because the mean of its divisors is an integer number (7625207059).

Almost surely, 215250414117 is an apocalyptic number.

It is an amenable number.

15250414117 is a deficient number, since it is larger than the sum of its proper divisors (1).

15250414117 is an equidigital number, since it uses as much as digits as its factorization.

15250414117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5600, while the sum is 31.

Adding to 15250414117 its reverse (71141405251), we get a palindrome (86391819368).

The spelling of 15250414117 in words is "fifteen billion, two hundred fifty million, four hundred fourteen thousand, one hundred seventeen".