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152504221433 is a prime number
BaseRepresentation
bin1000111000000111110…
…1011011111011111001
3112120122021121010212112
42032001331123323321
54444312040041213
6154020502422105
714006124331244
oct2160175337371
9476567533775
10152504221433
1159749725843
1225681431935
13114c53291a5
14754a1c025b
153e78890ea8
hex2381f5bef9

152504221433 has 2 divisors, whose sum is σ = 152504221434. Its totient is φ = 152504221432.

The previous prime is 152504221393. The next prime is 152504221447. The reversal of 152504221433 is 334122405251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87892682089 + 64611539344 = 296467^2 + 254188^2 .

It is a cyclic number.

It is not a de Polignac number, because 152504221433 - 216 = 152504155897 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 152504221433.

It is not a weakly prime, because it can be changed into another prime (152509221433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76252110716 + 76252110717.

It is an arithmetic number, because the mean of its divisors is an integer number (76252110717).

Almost surely, 2152504221433 is an apocalyptic number.

It is an amenable number.

152504221433 is a deficient number, since it is larger than the sum of its proper divisors (1).

152504221433 is an equidigital number, since it uses as much as digits as its factorization.

152504221433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 152504221433 its reverse (334122405251), we get a palindrome (486626626684).

The spelling of 152504221433 in words is "one hundred fifty-two billion, five hundred four million, two hundred twenty-one thousand, four hundred thirty-three".