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15270085541 is a prime number
BaseRepresentation
bin11100011100010101…
…10000001110100101
31110102012100201101202
432032022300032211
5222233120214131
611003122532245
71050256404554
oct161612601645
943365321352
1015270085541
116526624307
122b61b07085
1315947a1a99
14a4c04bd9b
155e58b4bcb
hex38e2b03a5

15270085541 has 2 divisors, whose sum is σ = 15270085542. Its totient is φ = 15270085540.

The previous prime is 15270085529. The next prime is 15270085543. The reversal of 15270085541 is 14558007251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12080208100 + 3189877441 = 109910^2 + 56479^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15270085541 is a prime.

Together with 15270085543, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 15270085495 and 15270085504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15270085543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7635042770 + 7635042771.

It is an arithmetic number, because the mean of its divisors is an integer number (7635042771).

Almost surely, 215270085541 is an apocalyptic number.

It is an amenable number.

15270085541 is a deficient number, since it is larger than the sum of its proper divisors (1).

15270085541 is an equidigital number, since it uses as much as digits as its factorization.

15270085541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56000, while the sum is 38.

The spelling of 15270085541 in words is "fifteen billion, two hundred seventy million, eighty-five thousand, five hundred forty-one".