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153000121 is a prime number
BaseRepresentation
bin10010001111010…
…01100010111001
3101122220012201011
421013221202321
5303132000441
623103153521
73535323331
oct1107514271
9348805634
10153000121
117940128a
12432a58a1
132590c621
141646a0c1
15d673581
hex91e98b9

153000121 has 2 divisors, whose sum is σ = 153000122. Its totient is φ = 153000120.

The previous prime is 153000091. The next prime is 153000131. The reversal of 153000121 is 121000351.

153000121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117418896 + 35581225 = 10836^2 + 5965^2 .

It is a cyclic number.

It is not a de Polignac number, because 153000121 - 223 = 144611513 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (153000131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76500060 + 76500061.

It is an arithmetic number, because the mean of its divisors is an integer number (76500061).

Almost surely, 2153000121 is an apocalyptic number.

It is an amenable number.

153000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

153000121 is an equidigital number, since it uses as much as digits as its factorization.

153000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 153000121 is about 12369.3217679871. The cubic root of 153000121 is about 534.8482651187.

Adding to 153000121 its reverse (121000351), we get a palindrome (274000472).

The spelling of 153000121 in words is "one hundred fifty-three million, one hundred twenty-one", and thus it is an aban number.