Base | Representation |
---|---|
bin | 1000111001111110100… |
… | …1101010101000110111 |
3 | 112121220222220222000100 |
4 | 2032133221222220313 |
5 | 10001322100332010 |
6 | 154142135245143 |
7 | 14024353363401 |
oct | 2163751525067 |
9 | 477828828010 |
10 | 153002355255 |
11 | 59984928092 |
12 | 257a02197b3 |
13 | 115745a9a29 |
14 | 759640bb71 |
15 | 3ea748b2c0 |
hex | 239fa6aa37 |
153002355255 has 12 divisors (see below), whose sum is σ = 265204082520. Its totient is φ = 81601256112.
The previous prime is 153002355227. The next prime is 153002355263. The reversal of 153002355255 is 552553200351.
153002355255 is a `hidden beast` number, since 1 + 5 + 30 + 0 + 23 + 552 + 55 = 666.
It is not a de Polignac number, because 153002355255 - 213 = 153002347063 is a prime.
It is a super-2 number, since 2×1530023552552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1700026125 + ... + 1700026214.
It is an arithmetic number, because the mean of its divisors is an integer number (22100340210).
Almost surely, 2153002355255 is an apocalyptic number.
153002355255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
153002355255 is a deficient number, since it is larger than the sum of its proper divisors (112201727265).
153002355255 is a wasteful number, since it uses less digits than its factorization.
153002355255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3400052350 (or 3400052347 counting only the distinct ones).
The product of its (nonzero) digits is 112500, while the sum is 36.
The spelling of 153002355255 in words is "one hundred fifty-three billion, two million, three hundred fifty-five thousand, two hundred fifty-five".
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