153004121 has 2 divisors, whose sum is σ = 153004122. Its totient is φ = 153004120.

The previous prime is 153004099. The next prime is 153004157. The reversal of 153004121 is 121400351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122323600 + 30680521 = 11060^2 + 5539^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-153004121 is a prime.

It is a super-2 number, since 2×153004121² = 46820522085965282, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 153004121.

It is not a weakly prime, because it can be changed into another prime (153004021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76502060 + 76502061.

It is an arithmetic number, because the mean of its divisors is an integer number (76502061).

Almost surely, 2^153004121 is an apocalyptic number.

It is an amenable number.

153004121 is a deficient number, since it is larger than the sum of its proper divisors (1).

153004121 is an equidigital number, since it uses as much as digits as its factorization.

153004121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 153004121 is about 12369.4834572831. The cubic root of 153004121 is about 534.8529260615.

Adding to 153004121 its reverse (121400351), we get a palindrome (274404472).

The spelling of 153004121 in words is "one hundred fifty-three million, four thousand, one hundred twenty-one".