Base | Representation |
---|---|
bin | 10110010001001101101… |
… | …010011101111001111001 |
3 | 12102022000000202112011210 |
4 | 112101031222131321321 |
5 | 200033034200214140 |
6 | 3131003150513333 |
7 | 215363353505136 |
oct | 26211552357171 |
9 | 5368000675153 |
10 | 1530311335545 |
11 | 540001943423 |
12 | 208702205849 |
13 | b1400147c05 |
14 | 540d319958d |
15 | 29c184c0d80 |
hex | 1644da9de79 |
1530311335545 has 8 divisors (see below), whose sum is σ = 2448498136896. Its totient is φ = 816166045616.
The previous prime is 1530311335529. The next prime is 1530311335589. The reversal of 1530311335545 is 5455331130351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1530311335545 - 24 = 1530311335529 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51010377837 + ... + 51010377866.
It is an arithmetic number, because the mean of its divisors is an integer number (306062267112).
Almost surely, 21530311335545 is an apocalyptic number.
1530311335545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1530311335545 is a deficient number, since it is larger than the sum of its proper divisors (918186801351).
1530311335545 is a wasteful number, since it uses less digits than its factorization.
1530311335545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 102020755711.
The product of its (nonzero) digits is 202500, while the sum is 39.
Adding to 1530311335545 its reverse (5455331130351), we get a palindrome (6985642465896).
The spelling of 1530311335545 in words is "one trillion, five hundred thirty billion, three hundred eleven million, three hundred thirty-five thousand, five hundred forty-five".
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