Base | Representation |
---|---|
bin | 100010110010111110010100… |
… | …100111111100011110000111 |
3 | 202001212010212221112202220112 |
4 | 202302332110213330132013 |
5 | 130024322144121114142 |
6 | 1301251552451223235 |
7 | 44143343320245641 |
oct | 4262762447743607 |
9 | 661763787482815 |
10 | 153036473223047 |
11 | 44842449533287 |
12 | 151b75b12a7b1b |
13 | 675137b897aab |
14 | 29b100d351891 |
15 | 12a5c6ac0e382 |
hex | 8b2f949fc787 |
153036473223047 has 2 divisors, whose sum is σ = 153036473223048. Its totient is φ = 153036473223046.
The previous prime is 153036473223031. The next prime is 153036473223079. The reversal of 153036473223047 is 740322374630351.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 153036473223047 - 24 = 153036473223031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153036473222986 and 153036473223004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153036473223097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76518236611523 + 76518236611524.
It is an arithmetic number, because the mean of its divisors is an integer number (76518236611524).
Almost surely, 2153036473223047 is an apocalyptic number.
153036473223047 is a deficient number, since it is larger than the sum of its proper divisors (1).
153036473223047 is an equidigital number, since it uses as much as digits as its factorization.
153036473223047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7620480, while the sum is 50.
The spelling of 153036473223047 in words is "one hundred fifty-three trillion, thirty-six billion, four hundred seventy-three million, two hundred twenty-three thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •