Base | Representation |
---|---|
bin | 100010110011001110001011… |
… | …011111111111101000101111 |
3 | 202001220202211120110022212110 |
4 | 202303032023133333220233 |
5 | 130030112032000404403 |
6 | 1301303450210335103 |
7 | 44144515260466164 |
oct | 4263161337775057 |
9 | 661822746408773 |
10 | 153053500013103 |
11 | 4484969672a6a8 |
12 | 151ba96358a493 |
13 | 6752b632ab0b1 |
14 | 29b1b8680606b |
15 | 12a6415929103 |
hex | 8b338b7ffa2f |
153053500013103 has 8 divisors (see below), whose sum is σ = 204081836868400. Its totient is φ = 102030414916608.
The previous prime is 153053500013083. The next prime is 153053500013107. The reversal of 153053500013103 is 301310005350351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 153053500013103 - 29 = 153053500012591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153053500013107) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1312871698 + ... + 1312988271.
It is an arithmetic number, because the mean of its divisors is an integer number (25510229608550).
Almost surely, 2153053500013103 is an apocalyptic number.
153053500013103 is a deficient number, since it is larger than the sum of its proper divisors (51028336855297).
153053500013103 is a wasteful number, since it uses less digits than its factorization.
153053500013103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2625879401.
The product of its (nonzero) digits is 10125, while the sum is 30.
Adding to 153053500013103 its reverse (301310005350351), we get a palindrome (454363505363454).
The spelling of 153053500013103 in words is "one hundred fifty-three trillion, fifty-three billion, five hundred million, thirteen thousand, one hundred three".
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