Base | Representation |
---|---|
bin | 100010110100001101011101… |
… | …110000010011001000010111 |
3 | 202002011021020021010112110101 |
4 | 202310031131300103020113 |
5 | 130032220213203341210 |
6 | 1301355005101434531 |
7 | 44152442216113252 |
oct | 4264153560231027 |
9 | 662137207115411 |
10 | 153121452012055 |
11 | 4487549687a21a |
12 | 1520bb6856ba47 |
13 | 67593a2342ab7 |
14 | 29b519142a099 |
15 | 12a8091344a3a |
hex | 8b435dc13217 |
153121452012055 has 4 divisors (see below), whose sum is σ = 183745742414472. Its totient is φ = 122497161609640.
The previous prime is 153121452012037. The next prime is 153121452012103. The reversal of 153121452012055 is 550210254121351.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-153121452012055 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15312145201201 + ... + 15312145201210.
It is an arithmetic number, because the mean of its divisors is an integer number (45936435603618).
Almost surely, 2153121452012055 is an apocalyptic number.
153121452012055 is a deficient number, since it is larger than the sum of its proper divisors (30624290402417).
153121452012055 is an equidigital number, since it uses as much as digits as its factorization.
153121452012055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30624290402416.
The product of its (nonzero) digits is 60000, while the sum is 37.
The spelling of 153121452012055 in words is "one hundred fifty-three trillion, one hundred twenty-one billion, four hundred fifty-two million, twelve thousand, fifty-five".
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