Base | Representation |
---|---|
bin | 10110010010000100011… |
… | …100000010111110010110 |
3 | 12102101101001221212022012 |
4 | 112102010130002332112 |
5 | 200041424424131402 |
6 | 3131234255304222 |
7 | 215425212550004 |
oct | 26220434027626 |
9 | 5371331855265 |
10 | 1531230302102 |
11 | 54043364a616 |
12 | 208919b1b072 |
13 | b15186524c7 |
14 | 5417d251a74 |
15 | 29c6dee7452 |
hex | 16484702f96 |
1531230302102 has 4 divisors (see below), whose sum is σ = 2296845453156. Its totient is φ = 765615151050.
The previous prime is 1531230302101. The next prime is 1531230302111. The reversal of 1531230302102 is 2012030321351.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×15312303021023 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1531230302101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 382807575524 + ... + 382807575527.
It is an arithmetic number, because the mean of its divisors is an integer number (574211363289).
Almost surely, 21531230302102 is an apocalyptic number.
1531230302102 is a deficient number, since it is larger than the sum of its proper divisors (765615151054).
1531230302102 is an equidigital number, since it uses as much as digits as its factorization.
1531230302102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 765615151053.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 1531230302102 its reverse (2012030321351), we get a palindrome (3543260623453).
The spelling of 1531230302102 in words is "one trillion, five hundred thirty-one billion, two hundred thirty million, three hundred two thousand, one hundred two".
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