Base | Representation |
---|---|
bin | 1000111010011101000… |
… | …1001001011011011101 |
3 | 112122020220101101021102 |
4 | 2032213101021123131 |
5 | 10002102304124001 |
6 | 154202542242445 |
7 | 14030464521614 |
oct | 2164721113335 |
9 | 478226341242 |
10 | 153130145501 |
11 | 59a3aa7a863 |
12 | 25816b86425 |
13 | 11594c00768 |
14 | 75a939487b |
15 | 3eb37cee6b |
hex | 23a74496dd |
153130145501 has 2 divisors, whose sum is σ = 153130145502. Its totient is φ = 153130145500.
The previous prime is 153130145471. The next prime is 153130145507. The reversal of 153130145501 is 105541031351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 150213605476 + 2916540025 = 387574^2 + 54005^2 .
It is a cyclic number.
It is not a de Polignac number, because 153130145501 - 230 = 152056403677 is a prime.
It is a super-2 number, since 2×1531301455012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153130145507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76565072750 + 76565072751.
It is an arithmetic number, because the mean of its divisors is an integer number (76565072751).
Almost surely, 2153130145501 is an apocalyptic number.
It is an amenable number.
153130145501 is a deficient number, since it is larger than the sum of its proper divisors (1).
153130145501 is an equidigital number, since it uses as much as digits as its factorization.
153130145501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 153130145501 its reverse (105541031351), we get a palindrome (258671176852).
The spelling of 153130145501 in words is "one hundred fifty-three billion, one hundred thirty million, one hundred forty-five thousand, five hundred one".
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