Base | Representation |
---|---|
bin | 1101111011010101111001… |
… | …0011010110111000101111 |
3 | 2000012220220002112011020022 |
4 | 3132311132103112320233 |
5 | 4001342302434334043 |
6 | 52322432030112355 |
7 | 3140223616661141 |
oct | 336653623267057 |
9 | 60186802464208 |
10 | 15313140543023 |
11 | 49742a2695294 |
12 | 187395794b6bb |
13 | 87103b58a61b |
14 | 3ad234cc8c91 |
15 | 1b84e3787868 |
hex | ded5e4d6e2f |
15313140543023 has 8 divisors (see below), whose sum is σ = 16213960963728. Its totient is φ = 14412325394304.
The previous prime is 15313140543013. The next prime is 15313140543031. The reversal of 15313140543023 is 32034504131351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 15313140543023 - 28 = 15313140542767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15313140543013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5742965 + ... + 7975457.
It is an arithmetic number, because the mean of its divisors is an integer number (2026745120466).
Almost surely, 215313140543023 is an apocalyptic number.
15313140543023 is a deficient number, since it is larger than the sum of its proper divisors (900820420705).
15313140543023 is a wasteful number, since it uses less digits than its factorization.
15313140543023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2635993.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 15313140543023 its reverse (32034504131351), we get a palindrome (47347644674374).
The spelling of 15313140543023 in words is "fifteen trillion, three hundred thirteen billion, one hundred forty million, five hundred forty-three thousand, twenty-three".
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