Base | Representation |
---|---|
bin | 11100100001100001… |
… | …10101000010010111 |
3 | 1110112020021120000110 |
4 | 32100300311002113 |
5 | 222330241334033 |
6 | 11011320014103 |
7 | 1051325426532 |
oct | 162060650227 |
9 | 43466246013 |
10 | 15313621143 |
11 | 654915a247 |
12 | 2b74601333 |
13 | 15a08059b2 |
14 | a53b41a19 |
15 | 5e9614363 |
hex | 390c35097 |
15313621143 has 4 divisors (see below), whose sum is σ = 20418161528. Its totient is φ = 10209080760.
The previous prime is 15313621069. The next prime is 15313621153. The reversal of 15313621143 is 34112631351.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 15313621143 - 214 = 15313604759 is a prime.
It is a super-2 number, since 2×153136211432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 15313621143.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15313621153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2552270188 + ... + 2552270193.
It is an arithmetic number, because the mean of its divisors is an integer number (5104540382).
Almost surely, 215313621143 is an apocalyptic number.
15313621143 is a deficient number, since it is larger than the sum of its proper divisors (5104540385).
15313621143 is an equidigital number, since it uses as much as digits as its factorization.
15313621143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5104540384.
The product of its digits is 6480, while the sum is 30.
The spelling of 15313621143 in words is "fifteen billion, three hundred thirteen million, six hundred twenty-one thousand, one hundred forty-three".
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