1531404041 has 4 divisors (see below), whose sum is σ = 1552973184. Its totient is φ = 1509834900.

The previous prime is 1531404031. The next prime is 1531404067. The reversal of 1531404041 is 1404041351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1531404041 - 2⁶ = 1531403977 is a prime.

It is a super-2 number, since 2×1531404041² = 4690396673582259362, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1531403998 and 1531404016.

It is not an unprimeable number, because it can be changed into a prime (1531404011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10784465 + ... + 10784606.

It is an arithmetic number, because the mean of its divisors is an integer number (388243296).

Almost surely, 2^1531404041 is an apocalyptic number.

It is an amenable number.

1531404041 is a deficient number, since it is larger than the sum of its proper divisors (21569143).

1531404041 is an equidigital number, since it uses as much as digits as its factorization.

1531404041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21569142.

The product of its (nonzero) digits is 960, while the sum is 23.

The square root of 1531404041 is about 39133.1578204468. The cubic root of 1531404041 is about 1152.6477218529.

Adding to 1531404041 its reverse (1404041351), we get a palindrome (2935445392).

The spelling of 1531404041 in words is "one billion, five hundred thirty-one million, four hundred four thousand, forty-one".