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15314053113103 = 211349207961177
BaseRepresentation
bin1101111011011001010010…
…1100100010010100001111
32000020000020200200112001011
43132312110230202110033
54001401140044104403
652323102345430051
73140255340462253
oct336662454422417
960200220615034
1015314053113103
114974720822738
121873b7149b327
13871155665614
143ad2c0198263
151b8548948a6d
hexded94b2250f

15314053113103 has 8 divisors (see below), whose sum is σ = 15430719407600. Its totient is φ = 15197802742080.

The previous prime is 15314053113101. The next prime is 15314053113157. The reversal of 15314053113103 is 30131135041351.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 15314053113103 - 21 = 15314053113101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15314053113101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 103906950 + ... + 104054227.

It is an arithmetic number, because the mean of its divisors is an integer number (1928839925950).

Almost surely, 215314053113103 is an apocalyptic number.

15314053113103 is a deficient number, since it is larger than the sum of its proper divisors (116666294497).

15314053113103 is a wasteful number, since it uses less digits than its factorization.

15314053113103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207961737.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 15314053113103 its reverse (30131135041351), we get a palindrome (45445188154454).

The spelling of 15314053113103 in words is "fifteen trillion, three hundred fourteen billion, fifty-three million, one hundred thirteen thousand, one hundred three".

Divisors: 1 211 349 73639 207961177 43879808347 72578450773 15314053113103