Base | Representation |
---|---|
bin | 1000111010100000011… |
… | …1010110001100010011 |
3 | 112122021220010020001122 |
4 | 2032220013112030103 |
5 | 10002114423303210 |
6 | 154204210552455 |
7 | 14031026345534 |
oct | 2165007261423 |
9 | 478256106048 |
10 | 153144353555 |
11 | 59a47aa4556 |
12 | 2581b89872b |
13 | 11597b367ab |
14 | 75ab21268b |
15 | 3eb4b89b55 |
hex | 23a81d6313 |
153144353555 has 4 divisors (see below), whose sum is σ = 183773224272. Its totient is φ = 122515482840.
The previous prime is 153144353543. The next prime is 153144353573. The reversal of 153144353555 is 555353441351.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 555353441351 = 2251 ⋅246714101.
It is not a de Polignac number, because 153144353555 - 216 = 153144288019 is a prime.
It is a super-2 number, since 2×1531443535552 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15314435351 + ... + 15314435360.
It is an arithmetic number, because the mean of its divisors is an integer number (45943306068).
Almost surely, 2153144353555 is an apocalyptic number.
153144353555 is a deficient number, since it is larger than the sum of its proper divisors (30628870717).
153144353555 is an equidigital number, since it uses as much as digits as its factorization.
153144353555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30628870716.
The product of its digits is 1350000, while the sum is 44.
The spelling of 153144353555 in words is "one hundred fifty-three billion, one hundred forty-four million, three hundred fifty-three thousand, five hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •