Base | Representation |
---|---|
bin | 11100100001110011… |
… | …11001110111110001 |
3 | 1110112101202102112012 |
4 | 32100321321313301 |
5 | 222331344001431 |
6 | 11011443012305 |
7 | 1051354565633 |
oct | 162071716761 |
9 | 43471672465 |
10 | 15316000241 |
11 | 654a534743 |
12 | 2b7536a095 |
13 | 15a1159849 |
14 | a541a0a53 |
15 | 5e993422b |
hex | 390e79df1 |
15316000241 has 2 divisors, whose sum is σ = 15316000242. Its totient is φ = 15316000240.
The previous prime is 15316000211. The next prime is 15316000243. The reversal of 15316000241 is 14200061351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13503369616 + 1812630625 = 116204^2 + 42575^2 .
It is a cyclic number.
It is not a de Polignac number, because 15316000241 - 210 = 15315999217 is a prime.
Together with 15316000243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (15316000243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7658000120 + 7658000121.
It is an arithmetic number, because the mean of its divisors is an integer number (7658000121).
Almost surely, 215316000241 is an apocalyptic number.
It is an amenable number.
15316000241 is a deficient number, since it is larger than the sum of its proper divisors (1).
15316000241 is an equidigital number, since it uses as much as digits as its factorization.
15316000241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 15316000241 its reverse (14200061351), we get a palindrome (29516061592).
The spelling of 15316000241 in words is "fifteen billion, three hundred sixteen million, two hundred forty-one", and thus it is an aban number.
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