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1531704426013 is a prime number
BaseRepresentation
bin10110010010100000101…
…100101011111000011101
312102102121010002212001001
4112102200230223320131
5200043412313113023
63131353313350301
7215443030542316
oct26224054537035
95372533085031
101531704426013
11540657242963
12208a30868391
13b15929476b8
14541c61cd60d
1529c9a94d6ad
hex164a0b2be1d

1531704426013 has 2 divisors, whose sum is σ = 1531704426014. Its totient is φ = 1531704426012.

The previous prime is 1531704425989. The next prime is 1531704426041. The reversal of 1531704426013 is 3106244071351.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1529582718169 + 2121707844 = 1236763^2 + 46062^2 .

It is a cyclic number.

It is not a de Polignac number, because 1531704426013 - 25 = 1531704425981 is a prime.

It is a super-2 number, since 2×15317044260132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1531707426013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765852213006 + 765852213007.

It is an arithmetic number, because the mean of its divisors is an integer number (765852213007).

Almost surely, 21531704426013 is an apocalyptic number.

It is an amenable number.

1531704426013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1531704426013 is an equidigital number, since it uses as much as digits as its factorization.

1531704426013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 37.

Adding to 1531704426013 its reverse (3106244071351), we get a palindrome (4637948497364).

The spelling of 1531704426013 in words is "one trillion, five hundred thirty-one billion, seven hundred four million, four hundred twenty-six thousand, thirteen".