Base | Representation |
---|---|
bin | 1000111010101101010… |
… | …1010111100111010111 |
3 | 112122102122202002102010 |
4 | 2032223111113213113 |
5 | 10002222240023142 |
6 | 154213420315303 |
7 | 14032253404014 |
oct | 2165325274727 |
9 | 478378662363 |
10 | 153198361047 |
11 | 59a75532146 |
12 | 258359a2b33 |
13 | 115a6095ca4 |
14 | 75b447070b |
15 | 3eb97a6e9c |
hex | 23ab5579d7 |
153198361047 has 8 divisors (see below), whose sum is σ = 204270512256. Its totient is φ = 102129225272.
The previous prime is 153198361039. The next prime is 153198361091. The reversal of 153198361047 is 740163891351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 153198361047 - 23 = 153198361039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153198360987 and 153198361005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153198361037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 632523 + ... + 840524.
It is an arithmetic number, because the mean of its divisors is an integer number (25533814032).
Almost surely, 2153198361047 is an apocalyptic number.
153198361047 is a deficient number, since it is larger than the sum of its proper divisors (51072151209).
153198361047 is a wasteful number, since it uses less digits than its factorization.
153198361047 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1507717.
The product of its (nonzero) digits is 544320, while the sum is 48.
The spelling of 153198361047 in words is "one hundred fifty-three billion, one hundred ninety-eight million, three hundred sixty-one thousand, forty-seven".
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