1532512340041 has 4 divisors (see below), whose sum is σ = 1539263495952. Its totient is φ = 1525761184132.

The previous prime is 1532512340027. The next prime is 1532512340083. The reversal of 1532512340041 is 1400432152351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1532512340041 - 2¹³ = 1532512331849 is a prime.

It is a super-2 number, since 2×1532512340041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1532512339985 and 1532512340012.

It is not an unprimeable number, because it can be changed into a prime (1532512340341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3375577615 + ... + 3375578068.

It is an arithmetic number, because the mean of its divisors is an integer number (384815873988).

Almost surely, 2^{1532512340041} is an apocalyptic number.

It is an amenable number.

1532512340041 is a deficient number, since it is larger than the sum of its proper divisors (6751155911).

1532512340041 is an equidigital number, since it uses as much as digits as its factorization.

1532512340041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6751155910.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1532512340041 its reverse (1400432152351), we get a palindrome (2932944492392).

The spelling of 1532512340041 in words is "one trillion, five hundred thirty-two billion, five hundred twelve million, three hundred forty thousand, forty-one".